Base | Representation |
---|---|
bin | 10000110001011000111… |
… | …000111000010100001011 |
3 | 11002011220200010102000021 |
4 | 100301120320320110023 |
5 | 122340401342303232 |
6 | 2241245402321311 |
7 | 146161035646321 |
oct | 20613070702413 |
9 | 4064820112007 |
10 | 1152542541067 |
11 | 404877243855 |
12 | 1674541b9237 |
13 | 848b8520768 |
14 | 3dad775dd11 |
15 | 1eea8676397 |
hex | 10c58e3850b |
1152542541067 has 2 divisors, whose sum is σ = 1152542541068. Its totient is φ = 1152542541066.
The previous prime is 1152542540993. The next prime is 1152542541083. The reversal of 1152542541067 is 7601452452511.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1152542541067 - 27 = 1152542540939 is a prime.
It is not a weakly prime, because it can be changed into another prime (1152542541097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576271270533 + 576271270534.
It is an arithmetic number, because the mean of its divisors is an integer number (576271270534).
Almost surely, 21152542541067 is an apocalyptic number.
1152542541067 is a deficient number, since it is larger than the sum of its proper divisors (1).
1152542541067 is an equidigital number, since it uses as much as digits as its factorization.
1152542541067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336000, while the sum is 43.
Adding to 1152542541067 its reverse (7601452452511), we get a palindrome (8753994993578).
The spelling of 1152542541067 in words is "one trillion, one hundred fifty-two billion, five hundred forty-two million, five hundred forty-one thousand, sixty-seven".
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