115300000241 has 2 divisors, whose sum is σ = 115300000242. Its totient is φ = 115300000240.

The previous prime is 115300000229. The next prime is 115300000243. The reversal of 115300000241 is 142000003511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114162894400 + 1137105841 = 337880^2 + 33721^2 .

It is a cyclic number.

It is not a de Polignac number, because 115300000241 - 2³⁰ = 114226258417 is a prime.

Together with 115300000243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (115300000243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57650000120 + 57650000121.

It is an arithmetic number, because the mean of its divisors is an integer number (57650000121).

Almost surely, 2^115300000241 is an apocalyptic number.

It is an amenable number.

115300000241 is a deficient number, since it is larger than the sum of its proper divisors (1).

115300000241 is an equidigital number, since it uses as much as digits as its factorization.

115300000241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

Adding to 115300000241 its reverse (142000003511), we get a palindrome (257300003752).

The spelling of 115300000241 in words is "one hundred fifteen billion, three hundred million, two hundred forty-one", and thus it is an aban number.