115300444345243 has 2 divisors, whose sum is σ = 115300444345244. Its totient is φ = 115300444345242.

The previous prime is 115300444345217. The next prime is 115300444345343. The reversal of 115300444345243 is 342543444003511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115300444345243 - 2²⁵ = 115300410790811 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115300444345243.

It is not a weakly prime, because it can be changed into another prime (115300444345043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57650222172621 + 57650222172622.

It is an arithmetic number, because the mean of its divisors is an integer number (57650222172622).

Almost surely, 2^{115300444345243} is an apocalyptic number.

115300444345243 is a deficient number, since it is larger than the sum of its proper divisors (1).

115300444345243 is an equidigital number, since it uses as much as digits as its factorization.

115300444345243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1382400, while the sum is 43.

Adding to 115300444345243 its reverse (342543444003511), we get a palindrome (457843888348754).

The spelling of 115300444345243 in words is "one hundred fifteen trillion, three hundred billion, four hundred forty-four million, three hundred forty-five thousand, two hundred forty-three".