115300444345343 has 2 divisors, whose sum is σ = 115300444345344. Its totient is φ = 115300444345342.

The previous prime is 115300444345243. The next prime is 115300444345459. The reversal of 115300444345343 is 343543444003511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115300444345343 - 2¹⁸ = 115300444083199 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115300444345294 and 115300444345303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115300444345043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57650222172671 + 57650222172672.

It is an arithmetic number, because the mean of its divisors is an integer number (57650222172672).

Almost surely, 2^{115300444345343} is an apocalyptic number.

115300444345343 is a deficient number, since it is larger than the sum of its proper divisors (1).

115300444345343 is an equidigital number, since it uses as much as digits as its factorization.

115300444345343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2073600, while the sum is 44.

Adding to 115300444345343 its reverse (343543444003511), we get a palindrome (458843888348854).

The spelling of 115300444345343 in words is "one hundred fifteen trillion, three hundred billion, four hundred forty-four million, three hundred forty-five thousand, three hundred forty-three".