Base | Representation |
---|---|
bin | 10101011110011111… |
… | …11001010000100001 |
3 | 1002202112221111001021 |
4 | 22233033321100201 |
5 | 142103202122311 |
6 | 5144042205441 |
7 | 555504231643 |
oct | 125717712041 |
9 | 32675844037 |
10 | 11530114081 |
11 | 49874a3402 |
12 | 22994b3881 |
13 | 11199c4615 |
14 | 7b5464893 |
15 | 4773a5171 |
hex | 2af3f9421 |
11530114081 has 2 divisors, whose sum is σ = 11530114082. Its totient is φ = 11530114080.
The previous prime is 11530114039. The next prime is 11530114097. The reversal of 11530114081 is 18041103511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6780699025 + 4749415056 = 82345^2 + 68916^2 .
It is a cyclic number.
It is not a de Polignac number, because 11530114081 - 27 = 11530113953 is a prime.
It is a super-2 number, since 2×115301140812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11530114181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5765057040 + 5765057041.
It is an arithmetic number, because the mean of its divisors is an integer number (5765057041).
Almost surely, 211530114081 is an apocalyptic number.
It is an amenable number.
11530114081 is a deficient number, since it is larger than the sum of its proper divisors (1).
11530114081 is an equidigital number, since it uses as much as digits as its factorization.
11530114081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 25.
Adding to 11530114081 its reverse (18041103511), we get a palindrome (29571217592).
The spelling of 11530114081 in words is "eleven billion, five hundred thirty million, one hundred fourteen thousand, eighty-one".
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