1153041137 has 2 divisors, whose sum is σ = 1153041138. Its totient is φ = 1153041136.

The previous prime is 1153041121. The next prime is 1153041139. The reversal of 1153041137 is 7311403511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 696748816 + 456292321 = 26396^2 + 21361^2 .

It is an emirp because it is prime and its reverse (7311403511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1153041137 - 2⁴ = 1153041121 is a prime.

It is a super-2 number, since 2×1153041137² = 2659007727228505538, which contains 22 as substring.

Together with 1153041139, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1153041139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576520568 + 576520569.

It is an arithmetic number, because the mean of its divisors is an integer number (576520569).

Almost surely, 2^1153041137 is an apocalyptic number.

It is an amenable number.

1153041137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1153041137 is an equidigital number, since it uses as much as digits as its factorization.

1153041137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260, while the sum is 26.

The square root of 1153041137 is about 33956.4594296873. The cubic root of 1153041137 is about 1048.6122670882.

Adding to 1153041137 its reverse (7311403511), we get a palindrome (8464444648).

The spelling of 1153041137 in words is "one billion, one hundred fifty-three million, forty-one thousand, one hundred thirty-seven".