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115304434142033 is a prime number
BaseRepresentation
bin11010001101111001100111…
…110101101000101101010001
3120010020222220021012200122002
4122031321213311220231101
5110103121440120021113
61045122043100323345
733200320240012223
oct3215714765505521
9503228807180562
10115304434142033
1133815377102544
1210b22931843555
134c45213a1c6b6
142068a9b6b0413
15d4e4eda22c58
hex68de67d68b51

115304434142033 has 2 divisors, whose sum is σ = 115304434142034. Its totient is φ = 115304434142032.

The previous prime is 115304434142021. The next prime is 115304434142057. The reversal of 115304434142033 is 330241434403511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103616356940944 + 11688077201089 = 10179212^2 + 3418783^2 .

It is a cyclic number.

It is not a de Polignac number, because 115304434142033 - 210 = 115304434141009 is a prime.

It is a super-2 number, since 2×1153044341420332 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115304434144033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57652217071016 + 57652217071017.

It is an arithmetic number, because the mean of its divisors is an integer number (57652217071017).

Almost surely, 2115304434142033 is an apocalyptic number.

It is an amenable number.

115304434142033 is a deficient number, since it is larger than the sum of its proper divisors (1).

115304434142033 is an equidigital number, since it uses as much as digits as its factorization.

115304434142033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 207360, while the sum is 38.

Adding to 115304434142033 its reverse (330241434403511), we get a palindrome (445545868545544).

The spelling of 115304434142033 in words is "one hundred fifteen trillion, three hundred four billion, four hundred thirty-four million, one hundred forty-two thousand, thirty-three".