Base | Representation |
---|---|
bin | 11010001101111010010110… |
… | …000110100010110110011111 |
3 | 120010021001220100201221110101 |
4 | 122031322112012202312133 |
5 | 110103130032320421211 |
6 | 1045122252104521531 |
7 | 33200345413325416 |
oct | 3215722606426637 |
9 | 503231810657411 |
10 | 115305210326431 |
11 | 33815735257354 |
12 | 10b22b097802a7 |
13 | 4c453087844c8 |
14 | 2068b327da47d |
15 | d4e546c435c1 |
hex | 68de961a2d9f |
115305210326431 has 2 divisors, whose sum is σ = 115305210326432. Its totient is φ = 115305210326430.
The previous prime is 115305210326389. The next prime is 115305210326477. The reversal of 115305210326431 is 134623012503511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115305210326431 - 245 = 80120838237599 is a prime.
It is a super-2 number, since 2×1153052103264312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115305220326431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57652605163215 + 57652605163216.
It is an arithmetic number, because the mean of its divisors is an integer number (57652605163216).
Almost surely, 2115305210326431 is an apocalyptic number.
115305210326431 is a deficient number, since it is larger than the sum of its proper divisors (1).
115305210326431 is an equidigital number, since it uses as much as digits as its factorization.
115305210326431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 37.
Adding to 115305210326431 its reverse (134623012503511), we get a palindrome (249928222829942).
The spelling of 115305210326431 in words is "one hundred fifteen trillion, three hundred five billion, two hundred ten million, three hundred twenty-six thousand, four hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •