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11532264841 is a prime number
BaseRepresentation
bin10101011110110000…
…00110010110001001
31002202200222202100001
422233120012112021
5142104224433331
65144200243001
7555531430246
oct125730062611
932680882301
1011532264841
114988732299
12229a170461
13111a298566
147b58645cd
1547767c561
hex2af606589

11532264841 has 2 divisors, whose sum is σ = 11532264842. Its totient is φ = 11532264840.

The previous prime is 11532264829. The next prime is 11532264853. The reversal of 11532264841 is 14846223511.

It is a balanced prime because it is at equal distance from previous prime (11532264829) and next prime (11532264853).

It can be written as a sum of positive squares in only one way, i.e., 10651065616 + 881199225 = 103204^2 + 29685^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11532264841 is a prime.

It is a super-3 number, since 3×115322648413 (a number of 31 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11532264841.

It is not a weakly prime, because it can be changed into another prime (11532264241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5766132420 + 5766132421.

It is an arithmetic number, because the mean of its divisors is an integer number (5766132421).

Almost surely, 211532264841 is an apocalyptic number.

It is an amenable number.

11532264841 is a deficient number, since it is larger than the sum of its proper divisors (1).

11532264841 is an equidigital number, since it uses as much as digits as its factorization.

11532264841 is an evil number, because the sum of its binary digits is even.

The product of its digits is 46080, while the sum is 37.

The spelling of 11532264841 in words is "eleven billion, five hundred thirty-two million, two hundred sixty-four thousand, eight hundred forty-one".