Base | Representation |
---|---|
bin | 10000110010000001111… |
… | …100010101110001010111 |
3 | 11002020200200011200212011 |
4 | 100302001330111301113 |
5 | 122343304204022012 |
6 | 2241442005205051 |
7 | 146214101300563 |
oct | 20620174256127 |
9 | 4066620150764 |
10 | 1153231314007 |
11 | 4050a0015093 |
12 | 167606a00787 |
13 | 8499812b906 |
14 | 3db610146a3 |
15 | 1eee8d7c1a7 |
hex | 10c81f15c57 |
1153231314007 has 2 divisors, whose sum is σ = 1153231314008. Its totient is φ = 1153231314006.
The previous prime is 1153231313881. The next prime is 1153231314071. The reversal of 1153231314007 is 7004131323511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1153231314007 - 211 = 1153231311959 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1153231314007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1153237314007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576615657003 + 576615657004.
It is an arithmetic number, because the mean of its divisors is an integer number (576615657004).
Almost surely, 21153231314007 is an apocalyptic number.
1153231314007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1153231314007 is an equidigital number, since it uses as much as digits as its factorization.
1153231314007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 1153231314007 its reverse (7004131323511), we get a palindrome (8157362637518).
The spelling of 1153231314007 in words is "one trillion, one hundred fifty-three billion, two hundred thirty-one million, three hundred fourteen thousand, seven".
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