Base | Representation |
---|---|
bin | 10101011110110001… |
… | …10110110000011010 |
3 | 1002202201100211100002 |
4 | 22233120312300122 |
5 | 142104302310010 |
6 | 5144204413002 |
7 | 555533214326 |
oct | 125730666032 |
9 | 32681324302 |
10 | 11532463130 |
11 | 4988858271 |
12 | 229a247162 |
13 | 111a3378a6 |
14 | 7b58b6986 |
15 | 4776bb1a5 |
hex | 2af636c1a |
11532463130 has 16 divisors (see below), whose sum is σ = 20761138944. Its totient is φ = 4612384080.
The previous prime is 11532463127. The next prime is 11532463133. The reversal of 11532463130 is 3136423511.
It is an interprime number because it is at equal distance from previous prime (11532463127) and next prime (11532463133).
It is a junction number, because it is equal to n+sod(n) for n = 11532463093 and 11532463102.
It is not an unprimeable number, because it can be changed into a prime (11532463133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10019 + ... + 152201.
It is an arithmetic number, because the mean of its divisors is an integer number (1297571184).
Almost surely, 211532463130 is an apocalyptic number.
11532463130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11532463130 is a deficient number, since it is larger than the sum of its proper divisors (9228675814).
11532463130 is a wasteful number, since it uses less digits than its factorization.
11532463130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 150301.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 11532463130 its reverse (3136423511), we get a palindrome (14668886641).
The spelling of 11532463130 in words is "eleven billion, five hundred thirty-two million, four hundred sixty-three thousand, one hundred thirty".
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