Base | Representation |
---|---|
bin | 110101101100111101… |
… | …1010011010100100001 |
3 | 102000200012222211212202 |
4 | 1223121323103110201 |
5 | 3342141242214301 |
6 | 124551342302545 |
7 | 11221604211464 |
oct | 1533173232441 |
9 | 360605884782 |
10 | 115325351201 |
11 | 44a00177305 |
12 | 1a426287a55 |
13 | ab4b8915a8 |
14 | 58205772db |
15 | 2eee8b966b |
hex | 1ad9ed3521 |
115325351201 has 2 divisors, whose sum is σ = 115325351202. Its totient is φ = 115325351200.
The previous prime is 115325351117. The next prime is 115325351203. The reversal of 115325351201 is 102153523511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112208920576 + 3116430625 = 334976^2 + 55825^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115325351201 is a prime.
Together with 115325351203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (115325351203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57662675600 + 57662675601.
It is an arithmetic number, because the mean of its divisors is an integer number (57662675601).
Almost surely, 2115325351201 is an apocalyptic number.
It is an amenable number.
115325351201 is a deficient number, since it is larger than the sum of its proper divisors (1).
115325351201 is an equidigital number, since it uses as much as digits as its factorization.
115325351201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 29.
Adding to 115325351201 its reverse (102153523511), we get a palindrome (217478874712).
The spelling of 115325351201 in words is "one hundred fifteen billion, three hundred twenty-five million, three hundred fifty-one thousand, two hundred one".
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