Base | Representation |
---|---|
bin | 1010011111010100001100… |
… | …1000100101000010110000 |
3 | 1111211112222111210002121110 |
4 | 2213311003020211002300 |
5 | 3002424304024341422 |
6 | 40310123400153320 |
7 | 2300145206234433 |
oct | 247650310450260 |
9 | 44745874702543 |
10 | 11533113512112 |
11 | 3747190a01145 |
12 | 1363240468840 |
13 | 65874c9b327a |
14 | 2bc2c451781a |
15 | 15000942d60c |
hex | a7d432250b0 |
11533113512112 has 20 divisors (see below), whose sum is σ = 29793876573080. Its totient is φ = 3844371170688.
The previous prime is 11533113512101. The next prime is 11533113512201. The reversal of 11533113512112 is 21121531133511.
It is a self number, because there is not a number n which added to its sum of digits gives 11533113512112.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120136599037 + ... + 120136599132.
It is an arithmetic number, because the mean of its divisors is an integer number (1489693828654).
Almost surely, 211533113512112 is an apocalyptic number.
11533113512112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11533113512112 is an abundant number, since it is smaller than the sum of its proper divisors (18260763060968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11533113512112 is a wasteful number, since it uses less digits than its factorization.
11533113512112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 240273198180 (or 240273198174 counting only the distinct ones).
The product of its digits is 2700, while the sum is 30.
Adding to 11533113512112 its reverse (21121531133511), we get a palindrome (32654644645623).
The spelling of 11533113512112 in words is "eleven trillion, five hundred thirty-three billion, one hundred thirteen million, five hundred twelve thousand, one hundred twelve".
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