11533134041573 has 2 divisors, whose sum is σ = 11533134041574. Its totient is φ = 11533134041572.

The previous prime is 11533134041503. The next prime is 11533134041581. The reversal of 11533134041573 is 37514043133511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11303057448004 + 230076593569 = 3362002^2 + 479663^2 .

It is a cyclic number.

It is not a de Polignac number, because 11533134041573 - 2¹⁶ = 11533133976037 is a prime.

It is a super-2 number, since 2×11533134041573² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11533134041573.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11533134041503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5766567020786 + 5766567020787.

It is an arithmetic number, because the mean of its divisors is an integer number (5766567020787).

Almost surely, 2^{11533134041573} is an apocalyptic number.

It is an amenable number.

11533134041573 is a deficient number, since it is larger than the sum of its proper divisors (1).

11533134041573 is an equidigital number, since it uses as much as digits as its factorization.

11533134041573 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 226800, while the sum is 41.

The spelling of 11533134041573 in words is "eleven trillion, five hundred thirty-three billion, one hundred thirty-four million, forty-one thousand, five hundred seventy-three".