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115340201453 is a prime number
BaseRepresentation
bin110101101101011001…
…1111100110111101101
3102000201020221022121002
41223122303330313231
53342204042421303
6124553032450045
711222144351621
oct1533263746755
9360636838532
10115340201453
1144a0859a544
121a42b249925
13ab51990a19
145822521181
153000d4e788
hex1adacfcded

115340201453 has 2 divisors, whose sum is σ = 115340201454. Its totient is φ = 115340201452.

The previous prime is 115340201419. The next prime is 115340201477. The reversal of 115340201453 is 354102043511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113975785609 + 1364415844 = 337603^2 + 36938^2 .

It is a cyclic number.

It is not a de Polignac number, because 115340201453 - 234 = 98160332269 is a prime.

It is a super-2 number, since 2×1153402014532 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115340206453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57670100726 + 57670100727.

It is an arithmetic number, because the mean of its divisors is an integer number (57670100727).

Almost surely, 2115340201453 is an apocalyptic number.

It is an amenable number.

115340201453 is a deficient number, since it is larger than the sum of its proper divisors (1).

115340201453 is an equidigital number, since it uses as much as digits as its factorization.

115340201453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 115340201453 its reverse (354102043511), we get a palindrome (469442244964).

The spelling of 115340201453 in words is "one hundred fifteen billion, three hundred forty million, two hundred one thousand, four hundred fifty-three".