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115341534124093 is a prime number
BaseRepresentation
bin11010001110011100001011…
…001010110101100000111101
3120010101112122211101001101201
4122032130023022311200331
5110104223430213432333
61045151100321535501
733203102511446224
oct3216341312654075
9503345584331351
10115341534124093
113382a08507a142
1210b29b664a4591
134c48877025cc4
14206a7baa5dcbb
15d50470b1517d
hex68e70b2b583d

115341534124093 has 2 divisors, whose sum is σ = 115341534124094. Its totient is φ = 115341534124092.

The previous prime is 115341534124079. The next prime is 115341534124121. The reversal of 115341534124093 is 390421435143511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104064114197124 + 11277419926969 = 10201182^2 + 3358187^2 .

It is an emirp because it is prime and its reverse (390421435143511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115341534124093 - 233 = 115332944189501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115341534134093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57670767062046 + 57670767062047.

It is an arithmetic number, because the mean of its divisors is an integer number (57670767062047).

Almost surely, 2115341534124093 is an apocalyptic number.

It is an amenable number.

115341534124093 is a deficient number, since it is larger than the sum of its proper divisors (1).

115341534124093 is an equidigital number, since it uses as much as digits as its factorization.

115341534124093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 777600, while the sum is 46.

The spelling of 115341534124093 in words is "one hundred fifteen trillion, three hundred forty-one billion, five hundred thirty-four million, one hundred twenty-four thousand, ninety-three".