Base | Representation |
---|---|
bin | 10000110010001111000… |
… | …000001101110110110001 |
3 | 11002021020221111010221022 |
4 | 100302033000031312301 |
5 | 122344231302341334 |
6 | 2241515433505225 |
7 | 146222401630361 |
oct | 20621700156661 |
9 | 4067227433838 |
10 | 1153450433969 |
11 | 4051a2777169 |
12 | 167668272215 |
13 | 84a0164b8b2 |
14 | 3db821729a1 |
15 | 2000d21182e |
hex | 10c8f00ddb1 |
1153450433969 has 2 divisors, whose sum is σ = 1153450433970. Its totient is φ = 1153450433968.
The previous prime is 1153450433917. The next prime is 1153450434029. The reversal of 1153450433969 is 9693340543511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 689298457600 + 464151976369 = 830240^2 + 681287^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1153450433969 is a prime.
It is a super-2 number, since 2×11534504339692 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1153450433969.
It is not a weakly prime, because it can be changed into another prime (1153450430969) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576725216984 + 576725216985.
It is an arithmetic number, because the mean of its divisors is an integer number (576725216985).
Almost surely, 21153450433969 is an apocalyptic number.
It is an amenable number.
1153450433969 is a deficient number, since it is larger than the sum of its proper divisors (1).
1153450433969 is an equidigital number, since it uses as much as digits as its factorization.
1153450433969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5248800, while the sum is 53.
The spelling of 1153450433969 in words is "one trillion, one hundred fifty-three billion, four hundred fifty million, four hundred thirty-three thousand, nine hundred sixty-nine".
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