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1153450433969 is a prime number
BaseRepresentation
bin10000110010001111000…
…000001101110110110001
311002021020221111010221022
4100302033000031312301
5122344231302341334
62241515433505225
7146222401630361
oct20621700156661
94067227433838
101153450433969
114051a2777169
12167668272215
1384a0164b8b2
143db821729a1
152000d21182e
hex10c8f00ddb1

1153450433969 has 2 divisors, whose sum is σ = 1153450433970. Its totient is φ = 1153450433968.

The previous prime is 1153450433917. The next prime is 1153450434029. The reversal of 1153450433969 is 9693340543511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 689298457600 + 464151976369 = 830240^2 + 681287^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1153450433969 is a prime.

It is a super-2 number, since 2×11534504339692 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1153450433969.

It is not a weakly prime, because it can be changed into another prime (1153450430969) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 576725216984 + 576725216985.

It is an arithmetic number, because the mean of its divisors is an integer number (576725216985).

Almost surely, 21153450433969 is an apocalyptic number.

It is an amenable number.

1153450433969 is a deficient number, since it is larger than the sum of its proper divisors (1).

1153450433969 is an equidigital number, since it uses as much as digits as its factorization.

1153450433969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5248800, while the sum is 53.

The spelling of 1153450433969 in words is "one trillion, one hundred fifty-three billion, four hundred fifty million, four hundred thirty-three thousand, nine hundred sixty-nine".