Base | Representation |
---|---|
bin | 10101011111000101… |
… | …00010000110110101 |
3 | 1002202220010201020211 |
4 | 22233202202012311 |
5 | 142110424444424 |
6 | 5144335025421 |
7 | 555563611402 |
oct | 125742420665 |
9 | 32686121224 |
10 | 11534999989 |
11 | 498a230247 |
12 | 229b06b271 |
13 | 111aa154a6 |
14 | 7b5d772a9 |
15 | 477a1cb94 |
hex | 2af8a21b5 |
11534999989 has 2 divisors, whose sum is σ = 11534999990. Its totient is φ = 11534999988.
The previous prime is 11534999941. The next prime is 11535000017. The reversal of 11534999989 is 98999943511.
11534999989 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10540102225 + 994897764 = 102665^2 + 31542^2 .
It is a cyclic number.
It is not a de Polignac number, because 11534999989 - 211 = 11534997941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11534999939) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5767499994 + 5767499995.
It is an arithmetic number, because the mean of its divisors is an integer number (5767499995).
Almost surely, 211534999989 is an apocalyptic number.
It is an amenable number.
11534999989 is a deficient number, since it is larger than the sum of its proper divisors (1).
11534999989 is an equidigital number, since it uses as much as digits as its factorization.
11534999989 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 28343520, while the sum is 67.
The spelling of 11534999989 in words is "eleven billion, five hundred thirty-four million, nine hundred ninety-nine thousand, nine hundred eighty-nine".
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