Base | Representation |
---|---|
bin | 110101101101101100… |
… | …1101010111001111011 |
3 | 102000201221112200020002 |
4 | 1223123121222321323 |
5 | 3342214110324324 |
6 | 124554024423215 |
7 | 11222324403362 |
oct | 1533331527173 |
9 | 360657480202 |
10 | 115350089339 |
11 | 44a13133451 |
12 | 1a432617b0b |
13 | ab53a43544 |
14 | 58239767d9 |
15 | 3001b543ae |
hex | 1adb66ae7b |
115350089339 has 2 divisors, whose sum is σ = 115350089340. Its totient is φ = 115350089338.
The previous prime is 115350089317. The next prime is 115350089369. The reversal of 115350089339 is 933980053511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115350089339 - 224 = 115333312123 is a prime.
It is a super-2 number, since 2×1153500893392 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 115350089293 and 115350089302.
It is not a weakly prime, because it can be changed into another prime (115350089369) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57675044669 + 57675044670.
It is an arithmetic number, because the mean of its divisors is an integer number (57675044670).
Almost surely, 2115350089339 is an apocalyptic number.
115350089339 is a deficient number, since it is larger than the sum of its proper divisors (1).
115350089339 is an equidigital number, since it uses as much as digits as its factorization.
115350089339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 437400, while the sum is 47.
The spelling of 115350089339 in words is "one hundred fifteen billion, three hundred fifty million, eighty-nine thousand, three hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •