Base | Representation |
---|---|
bin | 110101101110010010… |
… | …1101011001001010111 |
3 | 102000210100000220201111 |
4 | 1223130211223021113 |
5 | 3342234210411041 |
6 | 125000015435451 |
7 | 11222655634552 |
oct | 1533445531127 |
9 | 360710026644 |
10 | 115370013271 |
11 | 44a23401607 |
12 | 1a439225b87 |
13 | ab57bcb156 |
14 | 5826481699 |
15 | 300378c981 |
hex | 1adc96b257 |
115370013271 has 2 divisors, whose sum is σ = 115370013272. Its totient is φ = 115370013270.
The previous prime is 115370013223. The next prime is 115370013277. The reversal of 115370013271 is 172310073511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115370013271 - 29 = 115370012759 is a prime.
It is a super-2 number, since 2×1153700132712 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115370013277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57685006635 + 57685006636.
It is an arithmetic number, because the mean of its divisors is an integer number (57685006636).
Almost surely, 2115370013271 is an apocalyptic number.
115370013271 is a deficient number, since it is larger than the sum of its proper divisors (1).
115370013271 is an equidigital number, since it uses as much as digits as its factorization.
115370013271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4410, while the sum is 31.
Adding to 115370013271 its reverse (172310073511), we get a palindrome (287680086782).
The spelling of 115370013271 in words is "one hundred fifteen billion, three hundred seventy million, thirteen thousand, two hundred seventy-one".
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