11540133301 has 2 divisors, whose sum is σ = 11540133302. Its totient is φ = 11540133300.

The previous prime is 11540133289. The next prime is 11540133317. The reversal of 11540133301 is 10333104511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10174756900 + 1365376401 = 100870^2 + 36951^2 .

It is an emirp because it is prime and its reverse (10333104511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11540133301 - 2¹³ = 11540125109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11540134301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770066650 + 5770066651.

It is an arithmetic number, because the mean of its divisors is an integer number (5770066651).

Almost surely, 2^11540133301 is an apocalyptic number.

It is an amenable number.

11540133301 is a deficient number, since it is larger than the sum of its proper divisors (1).

11540133301 is an equidigital number, since it uses as much as digits as its factorization.

11540133301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 11540133301 its reverse (10333104511), we get a palindrome (21873237812).

The spelling of 11540133301 in words is "eleven billion, five hundred forty million, one hundred thirty-three thousand, three hundred one".