Base | Representation |
---|---|
bin | 110101101111001110… |
… | …1011111110111011111 |
3 | 102000212112010202121211 |
4 | 1223132131133313133 |
5 | 3342320231034401 |
6 | 125003101005251 |
7 | 11223516631213 |
oct | 1533635376737 |
9 | 360775122554 |
10 | 115401424351 |
11 | 44a3a106184 |
12 | 1a447853827 |
13 | ab615784a5 |
14 | 582a6da943 |
15 | 30063e4951 |
hex | 1ade75fddf |
115401424351 has 2 divisors, whose sum is σ = 115401424352. Its totient is φ = 115401424350.
The previous prime is 115401424301. The next prime is 115401424403. The reversal of 115401424351 is 153424104511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115401424351 - 213 = 115401416159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115401424301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57700712175 + 57700712176.
It is an arithmetic number, because the mean of its divisors is an integer number (57700712176).
Almost surely, 2115401424351 is an apocalyptic number.
115401424351 is a deficient number, since it is larger than the sum of its proper divisors (1).
115401424351 is an equidigital number, since it uses as much as digits as its factorization.
115401424351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 115401424351 its reverse (153424104511), we get a palindrome (268825528862).
The spelling of 115401424351 in words is "one hundred fifteen billion, four hundred one million, four hundred twenty-four thousand, three hundred fifty-one".
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