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1154020253 is a prime number
BaseRepresentation
bin100010011001000…
…1111001110011101
32222102111022011212
41010302033032131
54330412122003
6310302354205
740412003351
oct10462171635
92872438155
101154020253
11542461551
1228258b965
13155115c29
14ad3a1461
156b4a6dd8
hex44c8f39d

1154020253 has 2 divisors, whose sum is σ = 1154020254. Its totient is φ = 1154020252.

The previous prime is 1154020247. The next prime is 1154020279. The reversal of 1154020253 is 3520204511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 633176569 + 520843684 = 25163^2 + 22822^2 .

It is a cyclic number.

It is not a de Polignac number, because 1154020253 - 214 = 1154003869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1154020213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 577010126 + 577010127.

It is an arithmetic number, because the mean of its divisors is an integer number (577010127).

Almost surely, 21154020253 is an apocalyptic number.

It is an amenable number.

1154020253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1154020253 is an equidigital number, since it uses as much as digits as its factorization.

1154020253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 1154020253 is about 33970.8735978338. The cubic root of 1154020253 is about 1048.9089961866.

Adding to 1154020253 its reverse (3520204511), we get a palindrome (4674224764).

The spelling of 1154020253 in words is "one billion, one hundred fifty-four million, twenty thousand, two hundred fifty-three".