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115402578209 is a prime number
BaseRepresentation
bin110101101111010000…
…1111001100100100001
3102000212121022101102022
41223132201321210201
53342321030000314
6125003141431225
711223532505222
oct1533641714441
9360777271368
10115402578209
1144a3a824086
121a44810b515
13ab61890749
14582a91b249
15300657178e
hex1ade879921

115402578209 has 2 divisors, whose sum is σ = 115402578210. Its totient is φ = 115402578208.

The previous prime is 115402578143. The next prime is 115402578211. The reversal of 115402578209 is 902875204511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115394051809 + 8526400 = 339697^2 + 2920^2 .

It is a cyclic number.

It is not a de Polignac number, because 115402578209 - 212 = 115402574113 is a prime.

Together with 115402578211, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115402578209.

It is not a weakly prime, because it can be changed into another prime (115402578299) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57701289104 + 57701289105.

It is an arithmetic number, because the mean of its divisors is an integer number (57701289105).

Almost surely, 2115402578209 is an apocalyptic number.

It is an amenable number.

115402578209 is a deficient number, since it is larger than the sum of its proper divisors (1).

115402578209 is an equidigital number, since it uses as much as digits as its factorization.

115402578209 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 201600, while the sum is 44.

The spelling of 115402578209 in words is "one hundred fifteen billion, four hundred two million, five hundred seventy-eight thousand, two hundred nine".