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115403125121 is a prime number
BaseRepresentation
bin110101101111010001…
…1111111000110000001
3102000212122100011122022
41223132203333012001
53342321200000441
6125003201251225
711223540243554
oct1533643770601
9360778304568
10115403125121
1144a40067a79
121a448333b15
13ab61a2266b
14582aa2069b
15300662d84b
hex1ade8ff181

115403125121 has 2 divisors, whose sum is σ = 115403125122. Its totient is φ = 115403125120.

The previous prime is 115403125087. The next prime is 115403125147. The reversal of 115403125121 is 121521304511.

It is an a-pointer prime, because the next prime (115403125147) can be obtained adding 115403125121 to its sum of digits (26).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103442640625 + 11960484496 = 321625^2 + 109364^2 .

It is a cyclic number.

It is not a de Polignac number, because 115403125121 - 210 = 115403124097 is a prime.

It is not a weakly prime, because it can be changed into another prime (115403125151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57701562560 + 57701562561.

It is an arithmetic number, because the mean of its divisors is an integer number (57701562561).

Almost surely, 2115403125121 is an apocalyptic number.

It is an amenable number.

115403125121 is a deficient number, since it is larger than the sum of its proper divisors (1).

115403125121 is an equidigital number, since it uses as much as digits as its factorization.

115403125121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 26.

Adding to 115403125121 its reverse (121521304511), we get a palindrome (236924429632).

The spelling of 115403125121 in words is "one hundred fifteen billion, four hundred three million, one hundred twenty-five thousand, one hundred twenty-one".