Base | Representation |
---|---|
bin | 110101101111010010… |
… | …0000100000000100111 |
3 | 102000212122101012021000 |
4 | 1223132210010000213 |
5 | 3342321201122010 |
6 | 125003201524343 |
7 | 11223540356346 |
oct | 1533644040047 |
9 | 360778335230 |
10 | 115403145255 |
11 | 44a40081112 |
12 | 1a4483436b3 |
13 | ab61a2b888 |
14 | 582aa27b5d |
15 | 30066347c0 |
hex | 1ade904027 |
115403145255 has 64 divisors (see below), whose sum is σ = 215775498240. Its totient is φ = 58438972800.
The previous prime is 115403145251. The next prime is 115403145257. The reversal of 115403145255 is 552541304511.
115403145255 is a `hidden beast` number, since 1 + 1 + 540 + 3 + 14 + 52 + 55 = 666.
It is not a de Polignac number, because 115403145255 - 22 = 115403145251 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115403145251) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 38341 + ... + 481950.
It is an arithmetic number, because the mean of its divisors is an integer number (3371492160).
Almost surely, 2115403145255 is an apocalyptic number.
115403145255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
115403145255 is a deficient number, since it is larger than the sum of its proper divisors (100372352985).
115403145255 is a wasteful number, since it uses less digits than its factorization.
115403145255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 520389 (or 520383 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 36.
Adding to 115403145255 its reverse (552541304511), we get a palindrome (667944449766).
The spelling of 115403145255 in words is "one hundred fifteen billion, four hundred three million, one hundred forty-five thousand, two hundred fifty-five".
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