115403411353 has 2 divisors, whose sum is σ = 115403411354. Its totient is φ = 115403411352.

The previous prime is 115403411339. The next prime is 115403411393. The reversal of 115403411353 is 353114304511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81266045184 + 34137366169 = 285072^2 + 184763^2 .

It is a cyclic number.

It is not a de Polignac number, because 115403411353 - 2¹³ = 115403403161 is a prime.

It is not a weakly prime, because it can be changed into another prime (115403411393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57701705676 + 57701705677.

It is an arithmetic number, because the mean of its divisors is an integer number (57701705677).

Almost surely, 2^115403411353 is an apocalyptic number.

It is an amenable number.

115403411353 is a deficient number, since it is larger than the sum of its proper divisors (1).

115403411353 is an equidigital number, since it uses as much as digits as its factorization.

115403411353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 115403411353 its reverse (353114304511), we get a palindrome (468517715864).

The spelling of 115403411353 in words is "one hundred fifteen billion, four hundred three million, four hundred eleven thousand, three hundred fifty-three".