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115403411339 is a prime number
BaseRepresentation
bin110101101111010010…
…1000100111110001011
3102000212122212201020222
41223132211010332023
53342321233130324
6125003211340255
711223542545166
oct1533645047613
9360778781228
10115403411339
1144a40243017
121a44845168b
13ab61ac2a18
14582aa96add
15300668855e
hex1ade944f8b

115403411339 has 2 divisors, whose sum is σ = 115403411340. Its totient is φ = 115403411338.

The previous prime is 115403411317. The next prime is 115403411353. The reversal of 115403411339 is 933114304511.

It is a strong prime.

It is an emirp because it is prime and its reverse (933114304511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115403411339 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115403411299 and 115403411308.

It is not a weakly prime, because it can be changed into another prime (115403441339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57701705669 + 57701705670.

It is an arithmetic number, because the mean of its divisors is an integer number (57701705670).

Almost surely, 2115403411339 is an apocalyptic number.

115403411339 is a deficient number, since it is larger than the sum of its proper divisors (1).

115403411339 is an equidigital number, since it uses as much as digits as its factorization.

115403411339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 35.

The spelling of 115403411339 in words is "one hundred fifteen billion, four hundred three million, four hundred eleven thousand, three hundred thirty-nine".