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115403434493 is a prime number
BaseRepresentation
bin110101101111010010…
…1001010100111111101
3102000212122220220000112
41223132211022213331
53342321234400433
6125003212035405
711223543002534
oct1533645124775
9360778826015
10115403434493
1144a40259456
121a448462b65
13ab61b00419
14582aaa131b
153006690348
hex1ade94a9fd

115403434493 has 2 divisors, whose sum is σ = 115403434494. Its totient is φ = 115403434492.

The previous prime is 115403434463. The next prime is 115403434561. The reversal of 115403434493 is 394434304511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98121177049 + 17282257444 = 313243^2 + 131462^2 .

It is a cyclic number.

It is not a de Polignac number, because 115403434493 - 26 = 115403434429 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115403434493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115403434453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57701717246 + 57701717247.

It is an arithmetic number, because the mean of its divisors is an integer number (57701717247).

Almost surely, 2115403434493 is an apocalyptic number.

It is an amenable number.

115403434493 is a deficient number, since it is larger than the sum of its proper divisors (1).

115403434493 is an equidigital number, since it uses as much as digits as its factorization.

115403434493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 41.

The spelling of 115403434493 in words is "one hundred fifteen billion, four hundred three million, four hundred thirty-four thousand, four hundred ninety-three".