1154040335531 has 2 divisors, whose sum is σ = 1154040335532. Its totient is φ = 1154040335530.

The previous prime is 1154040335501. The next prime is 1154040335561. The reversal of 1154040335531 is 1355330404511.

It is a balanced prime because it is at equal distance from previous prime (1154040335501) and next prime (1154040335561).

It is an emirp because it is prime and its reverse (1355330404511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1154040335531 - 2¹⁴ = 1154040319147 is a prime.

It is a super-2 number, since 2×1154040335531² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1154040335491 and 1154040335500.

It is not a weakly prime, because it can be changed into another prime (1154040335501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 577020167765 + 577020167766.

It is an arithmetic number, because the mean of its divisors is an integer number (577020167766).

Almost surely, 2^{1154040335531} is an apocalyptic number.

1154040335531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1154040335531 is an equidigital number, since it uses as much as digits as its factorization.

1154040335531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 1154040335531 in words is "one trillion, one hundred fifty-four billion, forty million, three hundred thirty-five thousand, five hundred thirty-one".