Base | Representation |
---|---|
bin | 11010001111010110101010… |
… | …110100010011010000101101 |
3 | 120010121112210000200111020010 |
4 | 122033112222310103100231 |
5 | 110111241043040111300 |
6 | 1045240004535043433 |
7 | 33210455115525366 |
oct | 3217265264232055 |
9 | 503545700614203 |
10 | 115404342113325 |
11 | 338537855a1061 |
12 | 10b3a174810579 |
13 | 4c51776449985 |
14 | 206d858416b6d |
15 | d51de9b2ea50 |
hex | 68f5aad1342d |
115404342113325 has 24 divisors (see below), whose sum is σ = 190802426754976. Its totient is φ = 61548795000000.
The previous prime is 115404342113303. The next prime is 115404342113327. The reversal of 115404342113325 is 523311243404511.
It is not a de Polignac number, because 115404342113325 - 28 = 115404342113069 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115404342113327) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 24478950 + ... + 28810200.
Almost surely, 2115404342113325 is an apocalyptic number.
115404342113325 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
115404342113325 is a deficient number, since it is larger than the sum of its proper divisors (75398084641651).
115404342113325 is a wasteful number, since it uses less digits than its factorization.
115404342113325 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4686525 (or 4686520 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 39.
Adding to 115404342113325 its reverse (523311243404511), we get a palindrome (638715585517836).
The spelling of 115404342113325 in words is "one hundred fifteen trillion, four hundred four billion, three hundred forty-two million, one hundred thirteen thousand, three hundred twenty-five".
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