115406671 has 2 divisors, whose sum is σ = 115406672. Its totient is φ = 115406670.

The previous prime is 115406633. The next prime is 115406699. The reversal of 115406671 is 176604511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 115406671 - 2¹¹ = 115404623 is a prime.

It is a super-2 number, since 2×115406671² = 26637399422604482, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115406371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57703335 + 57703336.

It is an arithmetic number, because the mean of its divisors is an integer number (57703336).

Almost surely, 2^115406671 is an apocalyptic number.

115406671 is a deficient number, since it is larger than the sum of its proper divisors (1).

115406671 is an equidigital number, since it uses as much as digits as its factorization.

115406671 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 31.

The square root of 115406671 is about 10742.7496945614. The cubic root of 115406671 is about 486.8669614547.

The spelling of 115406671 in words is "one hundred fifteen million, four hundred six thousand, six hundred seventy-one".