115411121205013 has 2 divisors, whose sum is σ = 115411121205014. Its totient is φ = 115411121205012.

The previous prime is 115411121204983. The next prime is 115411121205031. The reversal of 115411121205013 is 310502121114511.

Together with next prime (115411121205031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115313728526929 + 97392678084 = 10738423^2 + 312078^2 .

It is a cyclic number.

It is not a de Polignac number, because 115411121205013 - 2²⁵ = 115411087650581 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115411121205113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57705560602506 + 57705560602507.

It is an arithmetic number, because the mean of its divisors is an integer number (57705560602507).

Almost surely, 2^{115411121205013} is an apocalyptic number.

It is an amenable number.

115411121205013 is a deficient number, since it is larger than the sum of its proper divisors (1).

115411121205013 is an equidigital number, since it uses as much as digits as its factorization.

115411121205013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 28.

Adding to 115411121205013 its reverse (310502121114511), we get a palindrome (425913242319524).

The spelling of 115411121205013 in words is "one hundred fifteen trillion, four hundred eleven billion, one hundred twenty-one million, two hundred five thousand, thirteen".