11541142414433 has 2 divisors, whose sum is σ = 11541142414434. Its totient is φ = 11541142414432.

The previous prime is 11541142414429. The next prime is 11541142414481. The reversal of 11541142414433 is 33441424114511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10911050963344 + 630091451089 = 3303188^2 + 793783^2 .

It is a cyclic number.

It is not a de Polignac number, because 11541142414433 - 2² = 11541142414429 is a prime.

It is a super-2 number, since 2×11541142414433² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11541142414733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5770571207216 + 5770571207217.

It is an arithmetic number, because the mean of its divisors is an integer number (5770571207217).

Almost surely, 2^{11541142414433} is an apocalyptic number.

It is an amenable number.

11541142414433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11541142414433 is an equidigital number, since it uses as much as digits as its factorization.

11541142414433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 92160, while the sum is 38.

Adding to 11541142414433 its reverse (33441424114511), we get a palindrome (44982566528944).

The spelling of 11541142414433 in words is "eleven trillion, five hundred forty-one billion, one hundred forty-two million, four hundred fourteen thousand, four hundred thirty-three".