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115414523400000 = 263551119920371
BaseRepresentation
bin11010001111100000001001…
…101010110100111101000000
3120010122112001120120102220210
4122033200021222310331000
5110111422420442300000
61045244411115234120
733211265324165046
oct3217401152647500
9503575046512823
10115414523400000
113385802a677470
1210b40136448940
134c5270986b866
14207014268a396
15d522e389c350
hex68f809ab4f40

115414523400000 has 672 divisors, whose sum is σ = 438299112061440. Its totient is φ = 26506656000000.

The previous prime is 115414523399953. The next prime is 115414523400023. The reversal of 115414523400000 is 4325414511.

115414523400000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 124939815 + ... + 125860185.

It is an arithmetic number, because the mean of its divisors is an integer number (652230821520).

Almost surely, 2115414523400000 is an apocalyptic number.

115414523400000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 115414523400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (219149556030720).

115414523400000 is an abundant number, since it is smaller than the sum of its proper divisors (322884588661440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

115414523400000 is an equidigital number, since it uses as much as digits as its factorization.

115414523400000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 920441 (or 920411 counting only the distinct ones).

The product of its (nonzero) digits is 9600, while the sum is 30.

Adding to 115414523400000 its reverse (4325414511), we get a palindrome (115418848814511).

The spelling of 115414523400000 in words is "one hundred fifteen trillion, four hundred fourteen billion, five hundred twenty-three million, four hundred thousand".