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115431232117 is a prime number
BaseRepresentation
bin110101110000000111…
…1001101001001110101
3102000221121020011012011
41223200033031021311
53342400343411432
6125010043524221
711224331166265
oct1534017151165
9360847204164
10115431232117
1144a54a151a3
121a455829671
13ab677b3b16
1458306597a5
153008d31847
hex1ae03cd275

115431232117 has 2 divisors, whose sum is σ = 115431232118. Its totient is φ = 115431232116.

The previous prime is 115431232031. The next prime is 115431232159. The reversal of 115431232117 is 711232134511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102559422001 + 12871810116 = 320249^2 + 113454^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115431232117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115401232117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57715616058 + 57715616059.

It is an arithmetic number, because the mean of its divisors is an integer number (57715616059).

Almost surely, 2115431232117 is an apocalyptic number.

It is an amenable number.

115431232117 is a deficient number, since it is larger than the sum of its proper divisors (1).

115431232117 is an equidigital number, since it uses as much as digits as its factorization.

115431232117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5040, while the sum is 31.

Adding to 115431232117 its reverse (711232134511), we get a palindrome (826663366628).

The spelling of 115431232117 in words is "one hundred fifteen billion, four hundred thirty-one million, two hundred thirty-two thousand, one hundred seventeen".