11543132001437 has 2 divisors, whose sum is σ = 11543132001438. Its totient is φ = 11543132001436.

The previous prime is 11543132001347. The next prime is 11543132001463. The reversal of 11543132001437 is 73410023134511.

11543132001437 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (11543132001347) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11432202371716 + 110929629721 = 3381154^2 + 333061^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11543132001437 is a prime.

It is a super-2 number, since 2×11543132001437² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11543132001397 and 11543132001406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11543132001337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5771566000718 + 5771566000719.

It is an arithmetic number, because the mean of its divisors is an integer number (5771566000719).

Almost surely, 2^{11543132001437} is an apocalyptic number.

It is an amenable number.

11543132001437 is a deficient number, since it is larger than the sum of its proper divisors (1).

11543132001437 is an equidigital number, since it uses as much as digits as its factorization.

11543132001437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30240, while the sum is 35.

Adding to 11543132001437 its reverse (73410023134511), we get a palindrome (84953155135948).

The spelling of 11543132001437 in words is "eleven trillion, five hundred forty-three billion, one hundred thirty-two million, one thousand, four hundred thirty-seven".