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11543132033551 is a prime number
BaseRepresentation
bin1010011111111001100001…
…0010001101001000001111
31111212111211201101201101001
42213332120102031020033
53003110313300033201
640314501444001131
72300651400246646
oct247763022151017
944774751351331
1011543132033551
113750462116628
1213651776901a7
13659688486b71
142bc994cdc35d
151503e3c49301
hexa7f9848d20f

11543132033551 has 2 divisors, whose sum is σ = 11543132033552. Its totient is φ = 11543132033550.

The previous prime is 11543132033471. The next prime is 11543132033581. The reversal of 11543132033551 is 15533023134511.

11543132033551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (15533023134511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11543132033551 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11543132033551.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11543132033581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5771566016775 + 5771566016776.

It is an arithmetic number, because the mean of its divisors is an integer number (5771566016776).

Almost surely, 211543132033551 is an apocalyptic number.

11543132033551 is a deficient number, since it is larger than the sum of its proper divisors (1).

11543132033551 is an equidigital number, since it uses as much as digits as its factorization.

11543132033551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81000, while the sum is 37.

The spelling of 11543132033551 in words is "eleven trillion, five hundred forty-three billion, one hundred thirty-two million, thirty-three thousand, five hundred fifty-one".