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11543132034347 is a prime number
BaseRepresentation
bin1010011111111001100001…
…0010001101010100101011
31111212111211201101202110112
42213332120102031110223
53003110313300044342
640314501444004535
72300651400252164
oct247763022152453
944774751352415
1011543132034347
113750462117191
12136517769074b
13659688487334
142bc994cdc76b
151503e3c49682
hexa7f9848d52b

11543132034347 has 2 divisors, whose sum is σ = 11543132034348. Its totient is φ = 11543132034346.

The previous prime is 11543132034289. The next prime is 11543132034349. The reversal of 11543132034347 is 74343023134511.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11543132034347 - 216 = 11543131968811 is a prime.

Together with 11543132034349, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11543132034349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5771566017173 + 5771566017174.

It is an arithmetic number, because the mean of its divisors is an integer number (5771566017174).

Almost surely, 211543132034347 is an apocalyptic number.

11543132034347 is a deficient number, since it is larger than the sum of its proper divisors (1).

11543132034347 is an equidigital number, since it uses as much as digits as its factorization.

11543132034347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 362880, while the sum is 41.

Adding to 11543132034347 its reverse (74343023134511), we get a palindrome (85886155168858).

The spelling of 11543132034347 in words is "eleven trillion, five hundred forty-three billion, one hundred thirty-two million, thirty-four thousand, three hundred forty-seven".