Base | Representation |
---|---|
bin | 10101100000000100… |
… | …11001110100111001 |
3 | 1002210110212011201212 |
4 | 22300002121310321 |
5 | 142120044322211 |
6 | 5145234052505 |
7 | 556024616165 |
oct | 126002316471 |
9 | 32713764655 |
10 | 11543354681 |
11 | 4993a17251 |
12 | 22a1a1a135 |
13 | 111c67c1b1 |
14 | 7b710dca5 |
15 | 47861d38b |
hex | 2b0099d39 |
11543354681 has 2 divisors, whose sum is σ = 11543354682. Its totient is φ = 11543354680.
The previous prime is 11543354659. The next prime is 11543354723. The reversal of 11543354681 is 18645334511.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6696967225 + 4846387456 = 81835^2 + 69616^2 .
It is a cyclic number.
It is not a de Polignac number, because 11543354681 - 214 = 11543338297 is a prime.
It is a super-2 number, since 2×115433546812 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (11543354611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5771677340 + 5771677341.
It is an arithmetic number, because the mean of its divisors is an integer number (5771677341).
Almost surely, 211543354681 is an apocalyptic number.
It is an amenable number.
11543354681 is a deficient number, since it is larger than the sum of its proper divisors (1).
11543354681 is an equidigital number, since it uses as much as digits as its factorization.
11543354681 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 172800, while the sum is 41.
The spelling of 11543354681 in words is "eleven billion, five hundred forty-three million, three hundred fifty-four thousand, six hundred eighty-one".
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