Base | Representation |
---|---|
bin | 110101110000001111… |
… | …1010011100001110101 |
3 | 102000221220011120111212 |
4 | 1223200133103201311 |
5 | 3342402433440113 |
6 | 125010314211205 |
7 | 11224412104562 |
oct | 1534037234165 |
9 | 360856146455 |
10 | 115435452533 |
11 | 44a57338045 |
12 | 1a457123b05 |
13 | ab68630acb |
14 | 5831037869 |
15 | 30093b70a8 |
hex | 1ae07d3875 |
115435452533 has 2 divisors, whose sum is σ = 115435452534. Its totient is φ = 115435452532.
The previous prime is 115435452499. The next prime is 115435452551. The reversal of 115435452533 is 335254534511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 114986775409 + 448677124 = 339097^2 + 21182^2 .
It is a cyclic number.
It is not a de Polignac number, because 115435452533 - 220 = 115434403957 is a prime.
It is a super-2 number, since 2×1154354525332 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115435452553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57717726266 + 57717726267.
It is an arithmetic number, because the mean of its divisors is an integer number (57717726267).
Almost surely, 2115435452533 is an apocalyptic number.
It is an amenable number.
115435452533 is a deficient number, since it is larger than the sum of its proper divisors (1).
115435452533 is an equidigital number, since it uses as much as digits as its factorization.
115435452533 is an evil number, because the sum of its binary digits is even.
The product of its digits is 540000, while the sum is 41.
The spelling of 115435452533 in words is "one hundred fifteen billion, four hundred thirty-five million, four hundred fifty-two thousand, five hundred thirty-three".
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