Base | Representation |
---|---|
bin | 110101110000010011… |
… | …1111111100110011111 |
3 | 102000222001110021220011 |
4 | 1223200213333212133 |
5 | 3342404024331312 |
6 | 125010435104051 |
7 | 11224440342202 |
oct | 1534047774637 |
9 | 360861407804 |
10 | 115437730207 |
11 | 44a58653318 |
12 | 1a457a42027 |
13 | ab68c4a747 |
14 | 583146b939 |
15 | 30096b6da7 |
hex | 1ae09ff99f |
115437730207 has 2 divisors, whose sum is σ = 115437730208. Its totient is φ = 115437730206.
The previous prime is 115437730169. The next prime is 115437730267. The reversal of 115437730207 is 702037734511.
It is a weak prime.
It is an emirp because it is prime and its reverse (702037734511) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115437730207 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 115437730207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115437730267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57718865103 + 57718865104.
It is an arithmetic number, because the mean of its divisors is an integer number (57718865104).
Almost surely, 2115437730207 is an apocalyptic number.
115437730207 is a deficient number, since it is larger than the sum of its proper divisors (1).
115437730207 is an equidigital number, since it uses as much as digits as its factorization.
115437730207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 123480, while the sum is 40.
The spelling of 115437730207 in words is "one hundred fifteen billion, four hundred thirty-seven million, seven hundred thirty thousand, two hundred seven".
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