115440573400693 has 2 divisors, whose sum is σ = 115440573400694. Its totient is φ = 115440573400692.

The previous prime is 115440573400679. The next prime is 115440573400717. The reversal of 115440573400693 is 396004375044511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84112798717809 + 31327774682884 = 9171303^2 + 5597122^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115440573400693 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115440573400693.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115440573407693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57720286700346 + 57720286700347.

It is an arithmetic number, because the mean of its divisors is an integer number (57720286700347).

Almost surely, 2^{115440573400693} is an apocalyptic number.

It is an amenable number.

115440573400693 is a deficient number, since it is larger than the sum of its proper divisors (1).

115440573400693 is an equidigital number, since it uses as much as digits as its factorization.

115440573400693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5443200, while the sum is 52.

The spelling of 115440573400693 in words is "one hundred fifteen trillion, four hundred forty billion, five hundred seventy-three million, four hundred thousand, six hundred ninety-three".