Base | Representation |
---|---|
bin | 11010001111111011101101… |
… | …011011101010011111010101 |
3 | 120010202100102211022201102012 |
4 | 122033323231123222133111 |
5 | 110112414021243342010 |
6 | 1045310143301554005 |
7 | 33213363526630160 |
oct | 3217735533523725 |
9 | 503670384281365 |
10 | 115444114434005 |
11 | 33869634a81275 |
12 | 10b45a14415905 |
13 | 4c554442a3336 |
14 | 207174c678ad7 |
15 | d52e76641005 |
hex | 68feed6ea7d5 |
115444114434005 has 16 divisors (see below), whose sum is σ = 161691939002880. Its totient is φ = 77477387436672.
The previous prime is 115444114433969. The next prime is 115444114434071. The reversal of 115444114434005 is 500434411444511.
It is a cyclic number.
It is not a de Polignac number, because 115444114434005 - 212 = 115444114429909 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35089394840 + ... + 35089398129.
It is an arithmetic number, because the mean of its divisors is an integer number (10105746187680).
Almost surely, 2115444114434005 is an apocalyptic number.
It is an amenable number.
115444114434005 is a deficient number, since it is larger than the sum of its proper divisors (46247824568875).
115444114434005 is an equidigital number, since it uses as much as digits as its factorization.
115444114434005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70178793028.
The product of its (nonzero) digits is 307200, while the sum is 41.
Adding to 115444114434005 its reverse (500434411444511), we get a palindrome (615878525878516).
The spelling of 115444114434005 in words is "one hundred fifteen trillion, four hundred forty-four billion, one hundred fourteen million, four hundred thirty-four thousand, five".
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