Base | Representation |
---|---|
bin | 11010001111111100000111… |
… | …100001000011100111111101 |
3 | 120010202101120022210011222001 |
4 | 122033330013201003213331 |
5 | 110112420420311232133 |
6 | 1045310254533422301 |
7 | 33213410422432036 |
oct | 3217740741034775 |
9 | 503671508704861 |
10 | 115444552055293 |
11 | 3386983a00265a |
12 | 10b45b16a9a991 |
13 | 4c554b3b57846 |
14 | 2071790833a8d |
15 | d52e9ec8687d |
hex | 68ff078439fd |
115444552055293 has 2 divisors, whose sum is σ = 115444552055294. Its totient is φ = 115444552055292.
The previous prime is 115444552055251. The next prime is 115444552055303. The reversal of 115444552055293 is 392550255444511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 77409678168729 + 38034873886564 = 8798277^2 + 6167242^2 .
It is a cyclic number.
It is not a de Polignac number, because 115444552055293 - 221 = 115444549958141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115444552055593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57722276027646 + 57722276027647.
It is an arithmetic number, because the mean of its divisors is an integer number (57722276027647).
Almost surely, 2115444552055293 is an apocalyptic number.
It is an amenable number.
115444552055293 is a deficient number, since it is larger than the sum of its proper divisors (1).
115444552055293 is an equidigital number, since it uses as much as digits as its factorization.
115444552055293 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21600000, while the sum is 55.
The spelling of 115444552055293 in words is "one hundred fifteen trillion, four hundred forty-four billion, five hundred fifty-two million, fifty-five thousand, two hundred ninety-three".
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