Base | Representation |
---|---|
bin | 1010100000000000111000… |
… | …1011101101100110000101 |
3 | 1111212200221120101000020202 |
4 | 2220000032023231212011 |
5 | 3003123341132334023 |
6 | 40315430023340245 |
7 | 2301051406122251 |
oct | 250001613554605 |
9 | 44780846330222 |
10 | 11545110043013 |
11 | 3751287703398 |
12 | 1365629bb1685 |
13 | 659912201a71 |
14 | 2bcb018b1261 |
15 | 1504ac716128 |
hex | a800e2ed985 |
11545110043013 has 2 divisors, whose sum is σ = 11545110043014. Its totient is φ = 11545110043012.
The previous prime is 11545110042971. The next prime is 11545110043067. The reversal of 11545110043013 is 31034001154511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11081162430244 + 463947612769 = 3328838^2 + 681137^2 .
It is an emirp because it is prime and its reverse (31034001154511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11545110043013 - 216 = 11545109977477 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11545110043513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5772555021506 + 5772555021507.
It is an arithmetic number, because the mean of its divisors is an integer number (5772555021507).
Almost surely, 211545110043013 is an apocalyptic number.
It is an amenable number.
11545110043013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11545110043013 is an equidigital number, since it uses as much as digits as its factorization.
11545110043013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 11545110043013 its reverse (31034001154511), we get a palindrome (42579111197524).
The spelling of 11545110043013 in words is "eleven trillion, five hundred forty-five billion, one hundred ten million, forty-three thousand, thirteen".
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