Base | Representation |
---|---|
bin | 11010010000001101010110… |
… | …110100111101110001101111 |
3 | 120010211011100100112102010021 |
4 | 122100031112310331301233 |
5 | 110113221323002342341 |
6 | 1045322555413423011 |
7 | 33214634220122626 |
oct | 3220152664756157 |
9 | 503734310472107 |
10 | 115463062543471 |
11 | 33876678765375 |
12 | 10b4962203aa67 |
13 | 4c57173a73026 |
14 | 2072628d866bd |
15 | d536d4d7a9d1 |
hex | 690356d3dc6f |
115463062543471 has 2 divisors, whose sum is σ = 115463062543472. Its totient is φ = 115463062543470.
The previous prime is 115463062543427. The next prime is 115463062543487. The reversal of 115463062543471 is 174345260364511.
It is a strong prime.
It is an emirp because it is prime and its reverse (174345260364511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115463062543471 - 29 = 115463062542959 is a prime.
It is a super-3 number, since 3×1154630625434713 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115463062544471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57731531271735 + 57731531271736.
It is an arithmetic number, because the mean of its divisors is an integer number (57731531271736).
Almost surely, 2115463062543471 is an apocalyptic number.
115463062543471 is a deficient number, since it is larger than the sum of its proper divisors (1).
115463062543471 is an equidigital number, since it uses as much as digits as its factorization.
115463062543471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7257600, while the sum is 52.
The spelling of 115463062543471 in words is "one hundred fifteen trillion, four hundred sixty-three billion, sixty-two million, five hundred forty-three thousand, four hundred seventy-one".
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