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115469001113 is a prime number
BaseRepresentation
bin110101110001001111…
…1010010000110011001
3102001001020022000111212
41223202133102012121
53342440031013423
6125013513232505
711225300213054
oct1534237220631
9361036260455
10115469001113
1144a74271644
121a466402735
13ab7257903b
14583568ba9b
15300c2e2578
hex1ae27d2199

115469001113 has 2 divisors, whose sum is σ = 115469001114. Its totient is φ = 115469001112.

The previous prime is 115469001083. The next prime is 115469001121. The reversal of 115469001113 is 311100964511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115445691529 + 23309584 = 339773^2 + 4828^2 .

It is an emirp because it is prime and its reverse (311100964511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115469001113 - 26 = 115469001049 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115469001113.

It is not a weakly prime, because it can be changed into another prime (115469001143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57734500556 + 57734500557.

It is an arithmetic number, because the mean of its divisors is an integer number (57734500557).

Almost surely, 2115469001113 is an apocalyptic number.

It is an amenable number.

115469001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

115469001113 is an equidigital number, since it uses as much as digits as its factorization.

115469001113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3240, while the sum is 32.

Adding to 115469001113 its reverse (311100964511), we get a palindrome (426569965624).

The spelling of 115469001113 in words is "one hundred fifteen billion, four hundred sixty-nine million, one thousand, one hundred thirteen".