Base | Representation |
---|---|
bin | 11010010000011010111111… |
… | …101110010100100010001011 |
3 | 120010212120010222020200210122 |
4 | 122100122333232110202023 |
5 | 110113441321032424433 |
6 | 1045333420521533455 |
7 | 33215663144443604 |
oct | 3220327756244213 |
9 | 503776128220718 |
10 | 115477707311243 |
11 | 33881903309132 |
12 | 10b5042a64428b |
13 | 4c58668b234a4 |
14 | 2073217d3adab |
15 | d53c908c1198 |
hex | 6906bfb9488b |
115477707311243 has 2 divisors, whose sum is σ = 115477707311244. Its totient is φ = 115477707311242.
The previous prime is 115477707311221. The next prime is 115477707311269. The reversal of 115477707311243 is 342113707774511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115477707311243 - 222 = 115477703116939 is a prime.
It is a super-2 number, since 2×1154777073112432 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115477707311273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57738853655621 + 57738853655622.
It is an arithmetic number, because the mean of its divisors is an integer number (57738853655622).
Almost surely, 2115477707311243 is an apocalyptic number.
115477707311243 is a deficient number, since it is larger than the sum of its proper divisors (1).
115477707311243 is an equidigital number, since it uses as much as digits as its factorization.
115477707311243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3457440, while the sum is 53.
The spelling of 115477707311243 in words is "one hundred fifteen trillion, four hundred seventy-seven billion, seven hundred seven million, three hundred eleven thousand, two hundred forty-three".
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