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115500510366253 is a prime number
BaseRepresentation
bin11010010000110000001110…
…111001000100101000101101
3120010221202000011012220122121
4122100300032321010220231
5110114330021123210003
61045352111342312541
733220431214301545
oct3220601671045055
9503852004186577
10115500510366253
1133890545011941
1210b54933288751
134c5a861157a4c
14207437c600325
15d5467777bcbd
hex690c0ee44a2d

115500510366253 has 2 divisors, whose sum is σ = 115500510366254. Its totient is φ = 115500510366252.

The previous prime is 115500510366229. The next prime is 115500510366289. The reversal of 115500510366253 is 352663015005511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 114801753135364 + 698757230889 = 10714558^2 + 835917^2 .

It is a cyclic number.

It is not a de Polignac number, because 115500510366253 - 221 = 115500508269101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115500510369253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57750255183126 + 57750255183127.

It is an arithmetic number, because the mean of its divisors is an integer number (57750255183127).

Almost surely, 2115500510366253 is an apocalyptic number.

It is an amenable number.

115500510366253 is a deficient number, since it is larger than the sum of its proper divisors (1).

115500510366253 is an equidigital number, since it uses as much as digits as its factorization.

115500510366253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 405000, while the sum is 43.

The spelling of 115500510366253 in words is "one hundred fifteen trillion, five hundred billion, five hundred ten million, three hundred sixty-six thousand, two hundred fifty-three".